시간 날짜, 요일 출력 초간단 예제 코드
#include <stdio.h>
#include <stdlib.h>
#include <time.h>
int main()
{
time_t ltime;
struct tm *today;
int daysofmonth[] = { 31, 28, 31, 30, 31, 30, 31, 31, 30, 31, 30, 31 };
char weekstr[][3] = { "일", "월", "화", "수", "목", "금", "토" };
int year, month, day, month2, th, rmd, adayofweek, OldSec=0;
while(1){
time(<ime);
today = localtime(<ime);
year = today->tm_year + 1900;
month = today->tm_mon + 1;
day = today->tm_mday;
if (month<=2) {
rmd = year-1;
month2 = month+12;
}
else {
rmd = year;
month2 = month;
}
th = rmd/100;
rmd %= 100;
adayofweek = (21*th/4 + 5*rmd/4 + 26*(month2+1)/10 + day-1) % 7;
if ( OldSec != today->tm_sec )
{
system("cls");
printf("%04d. %02d. %02d. (%s) %02d:%02d:%02d KST
",
// tm_year는 1900을 더해야 서기 연도가 됨
today->tm_year + 1900,
// tm_mon은 1월이 0, 2월이 1... 식으로 되어 있음
today->tm_mon + 1,
today->tm_mday,
weekstr[adayofweek],
today->tm_hour,
today->tm_min,
today->tm_sec);
OldSec = today->tm_sec;
}
}
return 0;
}