시간 날짜, 요일 출력 초간단 예제 코드
#include <stdio.h> #include <stdlib.h> #include <time.h> int main() { time_t ltime; struct tm *today; int daysofmonth[] = { 31, 28, 31, 30, 31, 30, 31, 31, 30, 31, 30, 31 }; char weekstr[][3] = { "일", "월", "화", "수", "목", "금", "토" }; int year, month, day, month2, th, rmd, adayofweek, OldSec=0; while(1){ time(<ime); today = localtime(<ime); year = today->tm_year + 1900; month = today->tm_mon + 1; day = today->tm_mday; if (month<=2) { rmd = year-1; month2 = month+12; } else { rmd = year; month2 = month; } th = rmd/100; rmd %= 100; adayofweek = (21*th/4 + 5*rmd/4 + 26*(month2+1)/10 + day-1) % 7; if ( OldSec != today->tm_sec ) { system("cls"); printf("%04d. %02d. %02d. (%s) %02d:%02d:%02d KST ", // tm_year는 1900을 더해야 서기 연도가 됨 today->tm_year + 1900, // tm_mon은 1월이 0, 2월이 1... 식으로 되어 있음 today->tm_mon + 1, today->tm_mday, weekstr[adayofweek], today->tm_hour, today->tm_min, today->tm_sec); OldSec = today->tm_sec; } } return 0; }