Leetcode
2020.05.07 03:50

# 720. Longest Word in Dictionary

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Given a list of strings `words` representing an English Dictionary, find the longest word in `words` that can be built one character at a time by other words in `words`. If there is more than one possible answer, return the longest word with the smallest lexicographical order.

If there is no answer, return the empty string.

Example 1:

```Input:
words = ["w","wo","wor","worl", "world"]
Output: "world"
Explanation:
The word "world" can be built one character at a time by "w", "wo", "wor", and "worl".
```

Example 2:

```Input:
words = ["a", "banana", "app", "appl", "ap", "apply", "apple"]
Output: "apple"
Explanation:
Both "apply" and "apple" can be built from other words in the dictionary. However, "apple" is lexicographically smaller than "apply".
```

Note:

• All the strings in the input will only contain lowercase letters.
• The length of `words` will be in the range `[1, 1000]`.
• The length of `words[i]` will be in the range `[1, 30]`.

• ```class Solution {
public String longestWord(String[] words) {
Map<Integer, String> hmap = new HashMap<>();
int max = Integer.MIN_VALUE;

for(String word : words){
Set<Character> set = new HashSet<>();
for(Character c : word.toCharArray()){
}

if(max <= set.size()){
max = set.size();
if(hmap.containsKey(max)){
if(word.compareTo(hmap.get(max)) > 0){
//hmap.remove(max);
hmap.put(max, word);
}
}else{
hmap.put(max, word);
}
}
}

if(hmap.containsKey(max)){
return hmap.get(max);
}

return "";
}
}```

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