Suppose you have a long flowerbed in which some of the plots are planted and some are not. However, flowers cannot be planted in adjacent plots - they would compete for water and both would die.
Given a flowerbed (represented as an array containing 0 and 1, where 0 means empty and 1 means not empty), and a number n, return if n new flowers can be planted in it without violating the no-adjacent-flowers rule.
Example 1:
Input: flowerbed = [1,0,0,0,1], n = 1 Output: True
Example 2:
Input: flowerbed = [1,0,0,0,1], n = 2 Output: False
Note:
- The input array won't violate no-adjacent-flowers rule.
- The input array size is in the range of [1, 20000].
- n is a non-negative integer which won't exceed the input array size.
class Solution {
public boolean canPlaceFlowers(int[] flowerbed, int n) {
for(int i=0; i<flowerbed.length; i++){
if(n == 0){
return true;
}
if(flowerbed[i] == 1){
continue;
}
boolean left = (i > 0) ? flowerbed[i - 1] == 0 : flowerbed[i] == 0;
boolean right = (i < flowerbed.length - 1) ? flowerbed[i + 1] == 0 : flowerbed[i] == 0;
if(left && right && flowerbed[i] == 0){
flowerbed[i] = 1;
n--;
}
}
return n <= 0;
}
}[문제] https://leetcode.com/problems/can-place-flowers/
